# Gas Pressure Loss through Piping

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

## Gas Pressure Loss through Piping formula

$$\large{ p_l = \frac { \mu \; l \; {v_g}^2 \; \rho } { 2 \; d } }$$
Symbol English Metric
$$\large{ p_l }$$ = gas pressure loss  $$\large{\frac{lbf}{in^2}}$$  $$\large{Pa}$$
$$\large{ \rho }$$  (Greek symbol rho) = density of gas $$\large{\frac{lbm}{ft^3}}$$ $$\large{\frac{kg}{m^3}}$$
$$\large{ v_g }$$ = velocity of gas $$\large{\frac{ft}{sec}}$$ $$\large{\frac{m}{s}}$$
$$\large{ \mu }$$  (Greek symbol mu) = friction coefficient $$\large{dimensionless}$$
$$\large{ d }$$ = inside diameter of pipe $$\large{in}$$ $$\large{mm}$$
$$\large{ l }$$ = pipe length $$\large{ft}$$ $$\large{m}$$