# Condensate Load from Heating Air

Written by Jerry Ratzlaff on . Posted in Fluid Dynamics

## Condensate Load from Heating Air formula

$$\large{ m_c = \frac { 60 \; c_a \; \gamma_a \; Q_a \; \left( T_o \;-\; T_i \right) } { L_s } }$$
Symbol English Metric
$$\large{ m_c }$$ = condensate load $$\large{lbm}$$ $$\large{kg}$$
$$\large{ Q_a }$$ = flow rate of air $$\large{\frac{ft^3}{sec}}$$ $$\large{\frac{m^3}{s}}$$
$$\large{ L_s }$$ = latent heat of steam $$\large{\frac{Btu}{lbm}}$$ $$\large{\frac{kJ}{kg}}$$
$$\large{ c_a }$$ = specific heat of air $$\large{\frac{Btu}{lbm-F}}$$ $$\large{\frac{kJ}{kg-K}}$$
$$\large{ \gamma_a }$$  (Greek symbol gamma) = specific weight of air $$\large{\frac{lbf}{ft^3}}$$ $$\large{\frac{N}{m^3}}$$
$$\large{ T_i }$$ = inlet temperature of air $$\large{F}$$ $$\large{K}$$
$$\large{ T_o }$$ = outlet temperature of air $$\large{F}$$ $$\large{K}$$