Heat Transfer by Conduction Resistance through a Cylindrical Wall

on . Posted in Thermodynamics

 

Heat Transfer by Conduction resistance through a Cylindrical Wall Formula

\( R_t \;=\;   ln \;  (   \frac  {r_2 }{ r_1 } ) \;/\; 2 \; \pi \; k \; l    \) 
Symbol English Metric
\( R_t \) = thermal resistance \(hr-F\;/\;Btu\) \(K\;/\;W\)
\( l \) = length of material \(ft\) \(m\)
\( ln \) = natural logarithm \(dimensionless\)
\( \pi \) = Pi \(3.141 592 653 ...\)
\( r_1 \) = radius inside diameter (ID) \(in\) \(mm\)
\( r_2\) = radius outside diameter (OD) \(in\) \(mm\)
\( k \) = thermal conductivity \(Btu-ft\;/\;hr-ft^2-F\) \(W\;/\;m-K\)

 

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Tags: Heat Transfer Heat