# Cylinder Axial Stress

on . Posted in Classical Mechanics

Cylinder axial stress, abbreviated as $$\sigma$$ (Greek symbol sigma), is the longitudinal stress parallel to the axis along a cylinder or pipe having both ends closed due to internal pressure.  When a cylindrical object, such as a pipe or a rod, is subjected to axial loading, the stress acting parallel to the axis is called axial stress.

It's important to note that axial stress represents the internal resistance within the cylindrical object due to the applied load.  Excessive axial stress can lead to deformation, failure, or structural instability of the cylinder, depending on the material properties and the design considerations.  Therefore, engineers and designers must carefully analyze the axial stress to ensure the structural integrity and safety of cylindrical components under axial loading conditions.

## Cylinder Axial Stress formula

$$\large{ \sigma = \frac{ p_i \; d }{ 4 \; t } }$$     (Cylinder Axial Stress)

$$\large{ p_i = \frac{ \sigma \; 4 \; t }{ d } }$$

$$\large{ t = \frac{ p_i \; d }{ \sigma \; 4 } }$$

$$\large{ d = \frac{ \sigma \; 4 \; t }{ p_i } }$$

### Solve for σ

 internal pressure, pi cylinder inside diameter, d wall thickness, t

### Solve for pi

 axial stress, σ wall thickness, t cylinder inside diameter, d

### Solve for d

 internal pressure, pi cylinder inside diameter, d axial stress, σ

### Solve for t

 axial stress, σ wall thickness, t internal pressure, pi

Symbol English Metric
$$\large{ \sigma }$$ (Greek symbol sigma) = axial stress  $$\large{\frac{lbf}{in^2}}$$ $$\large{Pa}$$
$$\large{ p_i }$$ = internal pressure $$\large{\frac{lbf}{in^2}}$$ $$\large{Pa}$$
$$\large{ d }$$ = cylinder inside diameter $$\large{ in }$$ $$\large{ mm }$$
$$\large{ t }$$ = wall thickness $$\large{ in }$$ $$\large{ mm }$$ Tags: Strain and Stress